CurvG
Spirals

Lituus

r²θ = a²: a shepherd’s-crook spiral named by Roger Cotes, whose sectors have equal area whenever their angles have equal ratio.

Adjust parameters

Export

Formulas and key values

Polar equation
r2θ=a2r^2\theta = a^2
r=aθr = \frac{a}{\sqrt\theta}
Asymptote
y=0y = 0
Area · sector between θ₁ and θ₂
A=a22ln⁡θ2θ1A = \frac{a^2}{2}\ln\frac{\theta_2}{\theta_1}

a sets the scale (a = 1 in the graph); θ > 0.

Explainer video

Make a video of the Lituus

Opens a video template with the parameters on screen. Every number in the video is computed before it renders; choose landscape or vertical.

Start the video

01 · Definition

What is the Lituus?

Roger Cotes named this spiral in 1722 after the lituus, the curved staff of a Roman augur, which it resembles: a long straight handle that curls into a coil. In polar form r = a/√θ.

Its sectors have a neat property. The area swept between angles θ₁ and θ₂ is (a²/2)·ln(θ₂/θ₁), so it depends only on their ratio. As θ → 0 the curve straightens out along the x-axis, its asymptote; as θ grows it coils ever more tightly around the pole.

02 · Properties

Key properties

  1. Polar equation r²θ = a², i.e. r = a/√θ.
  2. Sector area between θ₁ and θ₂: (a²/2)·ln(θ₂/θ₁).
  3. The x-axis is an asymptote as θ → 0.
  4. Winds into the pole as θ → ∞.
  5. Named by Roger Cotes in 1722.

03 · Questions

Lituus: common questions

What is the equation of the Lituus?
Polar equation: r^2θ = a^2, r = a/√θ. a sets the scale (a = 1 in the graph); θ > 0.
What is the area of the Lituus?
Area (sector between θ₁ and θ₂): A = ((a^2)/2)ln (θ₂)/(θ₁). a sets the scale (a = 1 in the graph); θ > 0.

04 · Keep exploring